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21x^2-59x-40=0
a = 21; b = -59; c = -40;
Δ = b2-4ac
Δ = -592-4·21·(-40)
Δ = 6841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{6841}}{2*21}=\frac{59-\sqrt{6841}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{6841}}{2*21}=\frac{59+\sqrt{6841}}{42} $
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